done for today I think

11-5-18.sql

@@ -1,27 +1,31 @@
 -- in class examples
 
+-- dataset is employee(name)
+
 -- first, always see the data you are working with
 SELECT * FROM employee;
 
 -- then, see the size of the data
 SELECT COUNT(*) FROM employee;
 
--- show winners of the nobel prize in 1950
+-- dataset is nobel(yr, subject, winner) (where winner is name)
+
+-- q1 show winners of the nobel prize in 1950
 SELECT yr, subject, winner FROM nobel
 WHERE yr = 1950;
 
--- show 1962 Literature prize winners
+-- q2 show 1962 Literature prize winners
 SELECT winner
 FROM nobel
-WHERE yr = 1950
+WHERE yr = 1950winner, subject, year
 AND subject = 'Literature';
 
--- find nobel prizes that Albert Einstein won
+-- q3 find nobel prizes that Albert Einstein won
 SELECT yr, subject
 FROM nobel
 WHERE winner = 'Albert Einstein';
 
--- Peace winners since 2000 inclusively
+-- q4 Peace winners since 2000 inclusively
 SELECT winner
 FROM nobel
 WHERE yr >= 2000
@@ -92,33 +96,89 @@ SELECT yr, subject, winner
 FROM nobel
 WHERE subject <> 'Chemistry' -- not equal is <>
 AND subject <> 'Medicine'
-AND yr = 1980
+AND yr = 1980;
 
 -- another one I came up with
 SELECT *
 FROM nobel
-WHERE yr = 1980 AND subject NOT IN ('Chemistry', 'Medicine')
+WHERE yr = 1980 AND subject NOT IN ('Chemistry', 'Medicine');
 
 -- another one he did
 SELECT *
 FROM nobel
 WHERE subject NOT IN ('Chemistry', 'Medicine')
-AND yr = 1980
+AND yr = 1980;
 
 -- q10 Show the info for the 'Medicine' prize before 1910, and Literature after 2004 inclusively
 SELECT *
 FROM nobel
 WHERE (subject = 'Literature' AND yr >= 2004)
-OR (subject = 'Medicine' AND yr < 1910)
+OR (subject = 'Medicine' AND yr < 1910);
 
 -- q11 Find all of the prizes by Peter Grünberg
 SELECT *
 FROM nobel
-WHERE name = 'Peter Grünberg'
+WHERE name = 'Peter Grünberg';
 
 -- he didn't expect this to work, lol. I think this newer database engine uses UTF-8 encoding for the data, and thus there is no problem there
 
 -- sad excuse for LIKE demonstrated here. He does mention it's bad to do this
 SELECT *
 FROM nobel
-WHERE name LIKE 'Peter Gr%nberg'
+WHERE name LIKE 'Peter Gr%nberg';
+
+-- can also use CHAR(252) to show ü. Not sure why you would need to do this since you can type this particular character, but I guess if your name has newlines in it that this would matter.
+SELECT *
+FROM nobel
+WHERE winner = 'Peter Gr' || CHAR(252) || 'nberg';
+
+-- q12 find this other guy
+SELECT *
+FROM nobel
+WHERE winner = 'Eugene O''Niell';
+
+-- q13 find winners that have names that start with 'Sir', and in the order name, year, subject
+SELECT winner, year, subject
+FROM nobel
+WHERE winner LIKE 'Sir %'
+ORDER BY yr DESC, winner;
+
+
+
+-- dataset is now world(name, continent, area, population, gdp)
+
+-- q1 list each country name where the population is larger than that of Russia
+SELECT name
+FROM world
+WHERE population > (
+  SELECT population
+  FROM world
+  WHERE name = 'Russia'
+);
+-- note - you can only expect one result to be returned from the nested query, otherwise it will fail. For example, returning all countries numbers that have an R to start the name of the country will fail.
+
+-- could have also done the population straight.
+SELECT name
+FROM world
+WHERE population > 1460000000;
+-- "cheating"
+
+-- q2 show the countries with a per capita GDP greater than the UK
+SELECT name
+FROM world
+WHERE continent = 'Europe'
+AND gdp/population > (
+  SELECT gdp/population AS percapitagdp
+  FROM world
+  WHERE name = 'United Kingdom'
+);
+
+-- q3 List the names and continent of countries in the continents containng either Argentena or Australia, and order by country
+SELECT name, continent
+FROM world
+WHERE continent IN (
+  SELECT continent
+  FROM world
+  WHERE name IN ('Argentena', 'Australia')
+)
+ORDER BY name;